A string fixed at both ends, oscillate in 4th harmonic. The displacement of particular wave is given as `Y=2Asin(5piX)cos(100pit)`. Then find the length of the string?
A string fixed at its both ends vibrates in 5 loops as shown in the figure
A string fixed at both the ends is vibrating in two segments. The wavelength of the corresponding wave is
A string is clamped at both the ends and it is vibrating in its 4^(th) harmonic. The equation of the stationary wave is Y=0.3 sin ( 0.157 x) cos (200 pi t) . The length of the string is: (All quantities are in SI units.)
The paritcle displacement (in cm) in a stationary wave is given by y(x,t)=2sin(0.1pix)cos(100pit) . The distance between a node and the next antinode is
A rope, under tension of 200N and fixed at both ends, oscialltes in a second harmonic standing wave pattern. The displacement of the rope is given by y=(0.10)sin ((pix)/(3)) sin (12 pit) , where x=0 at one end of the rope, x is in metres and t is in seconds. Find the length of the rope in metres.
The equation for the vibration of a string fixed at both ends vibrating in its third harmonic is given by y=2cm sin[(0.6cm^-1)x]cos[(500pis^-1)t] . The length of the string is
A stretched string fixed at both end has n nods, then the lengths of the string is
The equation for the vibration of a string fixed at both ends vibrating in its second harmonic is given by y=2sin(0.3cm^(-1))xcos((500pis^(-1))t)cm . The length of the string is :
If a string fixed at both ends vibrates in four loops. The wavelength is 10 cm. The length of string is
