For the circuit shown in the figure-3.352, calculate the charge on capacitor in steady state ?
The circuit consists of two resistors (of resistance R_(1) = 20 Omega and R_(2) = 10 Omega ), a capacitor (of capacitance C =10 muF ) and two ideal cells. In the circuit shown the capacitor is in steady state and the switch S is open The charge on capacitor in steady state with switch S closed.
For the circuit shown in the figure, find the charge stored on capacitor in steady state.
In the circuit shown in the figure K_(1) is open.The charge on capacitor C in steady state is q_(1) .Now key is closed and at steady state charge on C is q_(2) . The ratio of charges q_(1)/q_(2) is qquad R_(1)=2Omega E
In the circuit shown in figure. The charge on capacitor C_(2) in steady state is 10^(x) mu C . Find the value of x . .
Find the current flowing thorugh battery and charger on capacitor in steady state.
Find the charge stored in the capacitor in steady state in the circuit shown below.
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