The magnetic field of a plane electromagnetic wave is given by: `vec(B)=B_(0)hat(i)-[cos(kz- omegat)]+B_(1)hat(j)cos(kz+omegat)` where `B_(0)=3xx10^(-5)T` and `B_(1)=2xx10^(-6)T`. The rms value of the force experienced by a stationary charge `Q=10^(-4)C` at `z=0` is close to:
Magnetic field in a plane electromagnetic wave is given by bar(B) = B_(0)"sin"(kx + omegat)hat(j)T Expression for corresponding electric field will be
The magnetic field in a plane electromagnetic wave is given by B_(y) = 2 xx 10^(-7) sin (0.5 xx 10^(3)x + 1.5 xx 10^(11) t) . This electromagnetic wave is
The magnetic field in a plane EM wave is given by B = (100 mu T) sin [(2 x10^(15) s^(–1))(t – x//c)] hat(j) The equation for electric field is
The magnetic field in plane electromagnetic wave is given by B_(y) = 4 xx 10^(-6) sin (0.2 xx 10^(4) x + 0.6 xx 10^(12)t) T, then find i) Wavelength (ii) Speed of the wave
The magnetic field in the plane electromagnetic wave is given by B_(z)=2xx10^(-7) sin(0.5xx10^(3)x+1.5xx10^(11)t) tesla. The expression for electric field will be:
What is the intensity of a traveling plane electromagnetic wave if B_m" is " 3.0xx10^(-4) T ?
The magnetic field vector of an electromagnetic wave is given by B=B_(0)(hat(i)+hatj)/(sqrt(2))cos(kz-omegat) , where hati,hatj represents unit vector along x and y - axis repectively .At t=0 s , two electric charges q_(1) of 4pi coulomb and q_(2) of 2pi coulmb located at (0,0,(pi)/(k))and(0,0,(3pi)/(k)) , repectively ,have the same velocity of 0.5chati ,(where c is the velocity of light ).The ratio of the force actig on charge q_(1) to q_(2) is :
