A uniform wire of resistance `=3Omega` and length `l` is stretched to double its length. Now it is bent to form a circular loop and two point `P & Q` lies on the loop such that they subtend `60^(@)` angle at centre. The equivalent resistance between two point P & Q is:
A wire of resistance 1 Omega is stretched to double its length. Then its resistance becomes
A wire of resistance 1 Omega is stretched to double its length. What is the new resistance ?
If a wire of resistance 1Omega is stretched to double its length, then the resistnance will become
What is the effective resistance between points P and Q?
What is the effective resistance between points P and Q?
In the circuit shown in figure R=55 Omega the equivalent resistance between the point P and Q is
The equivalent resistance between the points P and Q of the circuit given is
A metal wire of resistance 3Omega is elongated to make a uniform wire of double its previous length. This new wire is now bent and the ends joined to make a circle. If two points on this circle make an angle 60^(@) at the center, the equivalent resistance between these two points will be :
The resistance of a wire is 2 Omega . The wire is stretched to doubel its length. Now the resistance of the wire will become
A wire of resistance 4 Omega is stretched to four times of its original length resistance of wire now becomes
