For position of real object at `x_(1)` and `x_(2) (x_(2)gtx_(1))` magnification is equal to 2. find out `(x_(1))/(x_(2))` if focal length of converging lens `f=20cm`
The magnifications produced by a convex lens for two different positions of an object are m_(1) and m_(2) respectively (m_(1) gt m_(2)) . If 'd' is the distance of separation between the two positions of the object then the focal length of the lens is
A thin converging lens forms the real image of certain real object magnified m times.The magnification of real image become n when lens is moved nearer to object by distance x . find focal length of the lens
The lateral magnification of the lens with an object located at two different position u_(1) and u_(2) are m_(1) and m_(2) , respectively. Then the focal length of the lens is
If f(x)=(x-1)/(x+1) then f(2x) is equal to
If f(x) = log ((1+x)/(1-x)) , then f((2x)/(1+x^(2))) is equal to
