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A position of particle is x=at+bt^(2)-ct...

A position of particle is `x=`at`+bt^(2)-ct^(3)` find out velocity when acceleration is zero (1) `v=a+b^2/(3c)` (2) `v=a-b^2/(3c)` (3) `v=2a-b^2/(3c)` (4) None of these

A

`v-a+(b^(2))/(3c)`

B

`v-a-(b^(2))/(3c)`

C

None of these

D

1

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The correct Answer is:
A
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