`ax + by = c " " bx + ay = 1 + c `
रेखिक समीकरणो के युग्मो को हल कीजिए :

Explanation

`ax + by = c " "rArr ax + by - c = 0`
`rArr " " bx + ay = 1 + c " " rArr bx + ay - (1 +c) = 0`
अब
`therefore (x)/(-b(1+c)+ac) = (y)/(-bc+a(1+c)) = (1)/(a^(2) - b^(2))`
`rArr (x)/(ac-b-bc) = (1)/(a^(2) -b^(2))`
और `(y)/(-bc +a+ac) = (1)/(a^(2) - b^(2))`
`rArr" "x = (ac -b - bc)/(a^(2) - b^(2))`
और `y = (a+ac -bc)/(a^(2) - b^(2))`