Two radioactive substances are having same initial number of nuclei. Disintegration constant of one substance is `10lamda`, other one `lamda` after how much time ratio of number of nuclei becomes `(1)/(e)`?
Two radioactive material A and B have disintegration constants 10lambda and2lambda respectively. If initially they have same number of nuclei, then the ration of number of nuclei of A and B will be (1)/(e) after a time of :
Two radioactive nuclei have same number of nuclei initially and decay constants as 5lambda . And 4lambda respectively. The ratio of number of nuclei will be 1/e^(2) after time:
Two radioactive substances have half-lives T and 2T. Initially, they have equal number of nuclei. After time t=4T , the ratio of their number of nuclei is x and the ratio of their activity is y. Then,
A radioactive substance has 10^8 nuclei. Its half life is 30 s . The number of nuclei left after 15 s is nearly
Two radioactive substance A and B have decay constants 5 lambda and lambda respectively. At t=0 they have the same number of nuclei. The ratio of number of nuclei of nuclei of A to those of B will be (1/e)^(2) after a time interval
Two radioactive substances A and B have half lives of T and 2T respectively. Samples of a and b contain equal number of nuclei initially. After a time 4T , the ratio of the number of undecayed nuclei of A to the number if undecayed nuclei of A to the number of undeacyed nuclei of B is
Two radioactive samples 1 and 2 have equal number of nuclei initially. They have halg-lives of 10 seconds and 20 seconds. The ratio of number of nuclei of 1 and 2 at t=60 seconds is :
Two radioactive substance X and Y initially contain equal number of nuclei. X has a half life of 1 hour and X has a half-life of 2 hours. After the ratio of activity of X to that of y is
Two radioactive substances X and Y originally have N_(1) and N_(2) nuclei respectively. Half life of X is half of the half life of Y. After three half lives of Y, number of nuclei of both are equal. (N_(1))/(N_(2)) The ratio N will be equal to :
