Equation of motion for a particle performing damped harmonic oscillation is given as `x=e^(-1t) cos(10pit+phi)`. The time when amplitude will half of the initial is :
The equation of a simple harmonic motion is given by , x=8sin(8pit)+6cos(8pit) . The initial phase angle is
The displacement of a damped harmonic oscillator is given by x(t)=e^(-0.1t)cos(10pit+phi) . Here t is in seconds The time taken for its amplitude of vibration to drop to half of its initial is close to :
A simple harmonic motion is given by y = 5(sin3pit + sqrt(3) cos3pit) . What is the amplitude of motion if y is in m ?
The equation of a simple harmonic motion is given by y=6 sin 10 pi t+8 cos 10 pi cm and t in sec. Determine the amplitude, period and initial phase.
The displacement of a simple harmonic oscillator is given by x = 4 cos (2pit+pi//4)m . Then velocity of the oscillator at t = 2 s is
The acceleration of a certain simple harmonic oscillator is given by a=-(35.28 m//s^(2))cos4.2t The amplitude of the simple harmonic motion is
The displacement of a particle executing simple harmonic motion is given by y=A_(0)+Asinomegat+Bcosomegat Then the amplitude of its oscillation is given by :
The displacement of a particle executing simple harmonic motion is given by y=A_(0)+A sin omegat+B cos omegat . Then the amplitude of its oscillation is given by
A simple harmonic motion is given by the equation x=10cos 10 pit . The phase of S.H.M. after time 2 s is
The instantaneous displacement x of a particle executing simple harmonic motion is given by x=a_1sinomegat+a_2cos(omegat+(pi)/(6)) . The amplitude A of oscillation is given by
