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Surface mass density of disc of mass m a...

Surface mass density of disc of mass `m` and radius `R` is `alpha-Kr^(2)`. Then its moment of inertia `w.r.t.` axis of rotation passing through center and perpendicular to the plane of disc is :

A

`1=(3)/(2)nR^(2)`

B

`1=(4)/(3)nR^(2)`

C

`1-(2)/(5)nR^(2)`

D

`1-(2)/(3)nR^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
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