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if vecE=E(0)cos(kz)cos(omegat)hati then ...

if `vecE=E_(0)cos(kz)cos(omegat)hati` then `vec(B)` for electromagentic wave is

A

`B=(E_(0))/(C)hat(k)`

B

`B=(E_(0))/(C)sin(k_(2)) sin(omegat)hat(j)`

C

`B=(E_(0))/(C)sin (kz)cos(omegat)hat(j)`

D

`B=(E_(0))/(C)cos(kz)sin(omegat)hat(j)`

Text Solution

Verified by Experts

The correct Answer is:
B
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