A particle is projected vertically upwards with speed `v_(0)`. The drag force acting on it given by `f_("drag")=mlambdav^(2)`. The time when it is at maximum height is :
A particle is projected vertically upwards in vacuum with a speed u .
A body is projected vertically upwards with a speed v_(0) . Find the magnitude of time average velocity of the body during its ascent.
A particle is fired vertically upward with a speed v_(0) . Find (a) Speed at distance 2R_(e) from centre of earth. (b) Calculated maximum height attained by particle.
A ball is projected vertically upward with speed of 50 m/s. Find a. the maximum height, b. the time to reach themaximum height, c. the speed at half the maximum height. Take g= 10 m/s^2 .
STATEMENT - 1 : A particle is projected vertically upwards with speed v. Starting from initial point, its average velocity is less than average speed than average speed when particle is returning back to ground. and STATEMENT - 2 : When particle turns back, its displacement is less than distance covered.
A particlele is projected vertically upwards from the ground with a speed V and a speed v and a second particle is projected at the same instant from a height h directly above the first particel with the same speed v at an angle of projection theta with the horizontal in upwards direction. The time when the distance between them is minimum is
A particle is projected vertically upward in vacum with a speed 40m//s then velocity of particle when it reaches at maximum height 2s before, is (Take g=10m//s )
A particle is projected vertically upwards from the surface of the earth (radius R_(e) ) with a speed equal to one fourth of escape velocity. What is the maximum height attained by it from the surface of the earth ?
A particle is projected vertically upward with velocity u from a point A , when it returns to the point of projection .
