The depression of mercury in a capillary tube of radius `R_(1)` is observed to be equal to the rise of water in another capillary tube of radius `R_(2)`. If the ratio of surface tension of mercury and water is `7.5`, ratio of their density `(p_(Hg))/(p_("water"))=13.6` and their angle of contact are `theta_(Hg)=135^(@)` and `theta_("water")=0^(@)` in the respective tubes then `R_(1)//R_(2)` is :
If a capillary tube of radius 1 mm is immersed in water , the mass of water rising in the capillary tube is M . If the radius tube is doubled , then the mass of water , that rises in the capillary tube will be
In a capillary tube, water rises to 3 mm . The height of water that will rise in another capillary tube having one-third radius of the first is
Water rises to a height h in a capillary tube of radius r. The mass of water in the capillary tube is 10 g. The mass of water rising in another capillary tube of radius 4r will be
In a capillary tube, water rises by 1.2mm . The height of water that will rise in another capillary tube having half the radius of the first, is
Water rises in a capillary tube of diameter 0.2xx10^(2)m upto a height of 1.5 cm. The surface tension of water is-
Water rises upto a height h in a capillary tube of radius r. What is the network done in this process if the density of water is rho ?
If h is the rise of water in a capillary tube of radius r, then the work done by the force of surface tension is (rho is density g = ("acc")^(n) due to gravity )
The rate of flow of water in a capillary tube of length l and radius r is V. The rate of flow in another capillary tube of length 21 and radius 2 r for same pressure difference would be
The lower end of a capillary tube of radius r is placed vertically in water of density rho , surface tension S. The rice of water in the capillary tube is upto height h, then heat evolved is
A capillary tube of radius r is lowered into a liquid of surface tension T and density rho . Given angle of contact =0^(@) . The work done by surface tension will be
