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The coordinates of a particle of mass 'm...

The coordinates of a particle of mass `'m'` as function of time are given by `x=x_(0)+a_(1) cos(omegat)` and `y=y_(0)+a_(2)sin(omega_(2)t)`. The torque on particle about origin at time `t=0` is :

A

`(ma_(1)omega_(1)^(2)x_(0))k^(hat)`

B

`(ma_(1)omega_(1)^(2)x_(0)^(2))k`

C

`(ma_(1)omega_(1)^(2)y_(0))k`

D

`(ma_(1)omega_(1)^(2)x_(0)y_(0))k`

Text Solution

Verified by Experts

The correct Answer is:
C
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