The distance covered by a particle in time t is given by `x=a+bt+ct^2+dt^3`, find the dimensions of a,b,c and d.

Explanation

To find the dimensions of the constants \(a\), \(b\), \(c\), and \(d\) in the equation \(x = a + bt + ct^2 + dt^3\), we start by recognizing that \(x\) represents distance.

### Step-by-Step Solution:

1. **Identify the Dimension of Distance**:
- The left-hand side (LHS) of the equation is \(x\), which represents distance. The dimension of distance is denoted as \(L\) (length).

2. **Analyze the First Term \(a\)**:
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