Taking foce, length and time to be the fundamental quantities find the dimension of
a. density, b. pressure,
c. momentum and d. energy

Answer

A, B, C, D

Explanation

Taking force, length and time as fundamental quantity (a) `Density = m/v = (force/acceleration)/Volume = ([F/LT^(-2)])/([L^3]) = F/(L^4 T^-2) = [FL^-4 T^2]` (b) Pressure `= F/A = F/L^2 = [FL^-2]` (c) Momentum `=mv = (Force/Acceleration) xx velocity = [F/LT^-2] xx [LT^-1] = [FT]` (d) Energy `= 1/2 mv^2 = Force/acceleration xx (velocity)^2 = [F/LT^-2] xx [LT^-1]^2 = [F/LT^-2] xx [L^2 T^-2 ] = [FL]`