The vectors `vecA` has a magnitude of 5 unit `vecB` has a magnitude of 6 unit and the cross product of `vecA and vecB` has a magnitude of 15 unit. Find the angle between `vecA and vecB`.

Explanation

If the angle between `vecA and vecB is theta`, the cross product will have a magnitude
`|vecAxxvecB|=AB sintheta`
OR, `15=5XX6 sintheta`
or, ` sin theta = 1/2`
thus,` theta= 30^0 or 150^0`.