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The resultant of vectors vec(OA) and vec...

The resultant of vectors `vec(OA) and vec(OB)` is peerpendicular to `vec(OA). Find the angle AOB.

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Take the dotted lines as X,Y axes.
x -component of `vec(OA)=4m, x-component of
`vec(OB)=6 m costheta`.
x- component of the resultant `=(4+6cos theta)` m.
But it is given that the resultant is along Y-axis. Thus, the -component of the resultant =0
`4+6cos theta = 0, or, costheta = 2/3`
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