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Find the area enclosed the curve y=sin x...

Find the area enclosed the curve y=sin x and the X-axis between `x=0 and x=pi`.

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The correct Answer is:
B

Area`= int^(x_2)_(x_1) y dx = int ^pi_0 sin x dx
=[cos x]^pi_0
= -cospi-(-cos0)
=+1+1=2`
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