The momentum p of a particle changes with the t according to the relation `dp/dt=(10N)+(2N/s)t`. If the momentum is zero at t=0, what will the momentum be at t=10?.

Answer

B

Explanation

`(dp)/(dt)=(10B)+(2N/S)t`
Momentum is zero t t=0
Momentum at t=10 sec will be
`dp= [(10N)+2N^(-1)t)]dt`
Integrating `int^10_0 dp=int^10_0 10 dt+ int ^10_0(2tdt)
=[10t+2t^2/2]^10_0
=10xx10-0+100
=100+100=200 kg. m/s`