A boy stretches a stone against the rubber tape of a catapult or gulel (a device used to detch mangoes from the tree by boys in Indian villages ) through a distance of 24 cm before leaving it. the tape returns to its normal positon acceleratiing the stone over the stretched length. The stone leaves the gulelwith a speed 2.2 m/s.Assuming that the acceleration is constant while the stone was being pushed by te tape, find its magnitude.

Explanation

Consider the accelerated 24 cm motion of the stone.
Initial velocity=0
FiN/Al velocity =2.2 m/s
Distance travelled =24 xm = 0.24 m
Using `v^2=u^2+2ax`
`a=(4.84 m^2/s^2)/(2xx0.24m)=10.1 m/s^2`