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A person travelling on a straight line m...

A person travelling on a straight line moves with a uniform velocity `v_1 for a distance x and with a uniform velocity `v_2` for the next equal distance. The average velocity v is given by

A

`v=(v_1+v_2)/2`

B

`v=sqrt(v_1v_2)`

C

`2/v=1/v_1+1/v_2`

D

`1/v=1/v_1+1/v_2`

Text Solution

AI Generated Solution

The correct Answer is:
To find the average velocity \( v \) of a person who travels equal distances \( x \) with two different uniform velocities \( v_1 \) and \( v_2 \), we can follow these steps: ### Step-by-Step Solution: 1. **Identify the total distance traveled**: The person travels a distance \( x \) at velocity \( v_1 \) and then another distance \( x \) at velocity \( v_2 \). Therefore, the total distance \( D \) is: \[ D = x + x = 2x \] 2. **Calculate the time taken for each segment**: - For the first segment (distance \( x \) at velocity \( v_1 \)): \[ t_1 = \frac{x}{v_1} \] - For the second segment (distance \( x \) at velocity \( v_2 \)): \[ t_2 = \frac{x}{v_2} \] 3. **Calculate the total time taken**: The total time \( T \) taken for the entire journey is the sum of the time taken for each segment: \[ T = t_1 + t_2 = \frac{x}{v_1} + \frac{x}{v_2} \] 4. **Factor out \( x \)**: We can factor out \( x \) from the total time equation: \[ T = x \left( \frac{1}{v_1} + \frac{1}{v_2} \right) \] 5. **Calculate the average velocity**: The average velocity \( v \) is defined as the total distance divided by the total time: \[ v = \frac{D}{T} = \frac{2x}{T} \] Substituting \( T \) from the previous step: \[ v = \frac{2x}{x \left( \frac{1}{v_1} + \frac{1}{v_2} \right)} = \frac{2}{\frac{1}{v_1} + \frac{1}{v_2}} \] 6. **Simplify the expression**: The average velocity can be expressed as: \[ \frac{2}{\frac{1}{v_1} + \frac{1}{v_2}} = \frac{2v_1v_2}{v_1 + v_2} \] ### Final Result: Thus, the average velocity \( v \) is given by: \[ v = \frac{2v_1v_2}{v_1 + v_2} \]
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