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A person standing near the edge of the t...

A person standing near the edge of the top of a building throws two balls A and B. The ball A is thrown vertically upward and B is thrown vertically downward with the same speed. The ball A hits the ground with speed `v_A` and the ball B hits the ground wiht a speed `v_B`. We have

A

`v_Altv_B`

B

`v_Altv_B`

C

`v_A=v_B`

D

the relation between `v_A and v_B` depends on height of the building above the ground.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the motion of both balls A and B as they are thrown from the top of a building. ### Step-by-Step Solution: 1. **Understanding the Situation:** - A person throws two balls from the top of a building: Ball A is thrown vertically upward and Ball B is thrown vertically downward with the same initial speed (let's denote this speed as \( u \)). - Both balls are thrown from the same height \( H \) (the height of the building). 2. **Analyzing Ball A (Thrown Upward):** - When Ball A is thrown upward, it will first move against gravity, reach a maximum height, and then fall back down to the ground. - The final speed of Ball A when it hits the ground can be calculated using the kinematic equation: \[ v_A^2 = u^2 + 2gh \] Here, \( g \) is the acceleration due to gravity (acting downward), and \( h \) is the total height from which it falls (which is \( H \)). 3. **Analyzing Ball B (Thrown Downward):** - Ball B is thrown downward with the same initial speed \( u \). - The final speed of Ball B when it hits the ground can also be calculated using the same kinematic equation: \[ v_B^2 = u^2 + 2gh \] The displacement is the same \( H \) since it is also falling from the same height. 4. **Comparing the Final Speeds:** - Since both balls are thrown with the same initial speed \( u \) and fall the same distance \( H \), we can equate the two equations: \[ v_A^2 = u^2 + 2gH \] \[ v_B^2 = u^2 + 2gH \] - From these equations, we can see that: \[ v_A^2 = v_B^2 \] - Taking the square root of both sides gives us: \[ v_A = v_B \] 5. **Conclusion:** - Therefore, the final speeds of both balls when they hit the ground are equal: \[ v_A = v_B \] ### Final Answer: The relation between \( v_A \) and \( v_B \) is: \[ v_A = v_B \]
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