At what distance should two charges, each equalk to 1C, be placed so that the force between them equals your weight?

Answer

A

Explanation

Force of attraction betwenteh two charges
`= 1/ (4pi epsilon_0 (q_1 q_2)/r^2`
` (9xx10^9xx1xx1`/r^2`
But force of attraction is equal of the weight,
`:. Mg= (9xx10^9)/r^2`
`rarr r^2 = (9xx10^9)/(mxx10) = (9xx10^8)/m`
taking g= 10 m/s^2
`rarr r^2 = (9xx10^8)/m `
`rarr r= (3xx10^4)./m m `
e.g Assuming `m= 64 kg`
` r= (3xx10^4)/(sqrt(64))`
` 3/8xx10^4 m`
=3750 m.