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Two charged particles placed at a separa...

Two charged particles placed at a separation of 20 cm exert 20 N of coulomb force on each other. What will be the force if the separation is increased to 25 cm?

Text Solution

Verified by Experts

The correct Answer is:
A, C
Here `F_1 = 1/(4 pi epsilon_0) , q^2/ r_1^2 `
and ` F_2 = 1/ 4pi epsilon_0) , q^2 /r_2^2 `,
`:. F_2/F_1 =r_1^2/ r_2^2`
`= (20xx20)/(25xx25)= 16/25`
`:. F-2 = 16/25xx20`
12.8 N.
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