The geostationary orbit of the earth is at a distance of about 36000 km from the earth's surface. Find the weight of a 120 kg equipment placed in a geostationary satellite. The radius of the earth is 6400 km.

Answer

B

Explanation

The geostatioN/Ary orbit of earth is at a distance of about 3600 km K
WE know, `g' = (Gm)/((R+h)^2))
At `h= 36000 km`
g'= Gm/(36000+6400)^2)`
t the surface,
`g' = Gm/((6400))^2`
`:. G'/g= (6400xx6400)/(42400xx42400)`
256/(106xx106)= 0.0227`
`rarr g'= 0.0277x9.8=0.223`
[taking g= 9.8 m/s^2 at the surface fo the earth.]
A 120 kg equipment placed in a geostatioN/Ary satellite will have weight
` mg'= 0.233xx120`
`= 26.79 27N`.