A heavy particle of mass 0.50 kg is hanging from a string fixed with the roof. Find the force exerted by the string on the particle. `Take g=9.8 m/s^2`
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Options

A. T is 9.9 N acting vertically upward
B. T is 4.9 N acting vertically upward
C. T is 4.9 N acting vertically downward
D. T is 14.9 N acting vertically upward

Answer

B

Explanation

The forces acting on the particle are a. pull of the earth `0.50 kg xx 9.8 m/s^2=4.9N` vertically downward
b. pull of the string . T vertically upward.
the particle is at rest with respect to the earth (which we assume to be an inertial frame). Hence, the sum of the forces should be zero. Therefore, T is 4.9 N acting vertically upward.