Two small kids weighing 10 g and 15 kg respectively are tyribg t balance a seesaw of total length 5.0 with the fulcrum at the centre. If one of the kids is sitting at an end where shold the other sit?

Explanation

It is clear that the 10 kg kid shoud silt at the end and the 15 kg kid should silt closer to the centre. Supose his distance from tehcentre is x. As the kids are in equilibriu, the normal force between a kid and the seesaw equals the weight of that kid. Considering the rotatioN/Al equilibrium of the seesaw, the torques of the forces acting on it shold add to zero. The forces are
a. (15kg)g downward by the 15 kg kid,
(10kg) g downward by the 10 kg kid
c. weight of the seesaw and
d. the normal forces by the fulcrum,
`(15kg)gx=(10kg)g(2.5m)`
`or, x=1.7m`