Consider the following two equations
`L=Iomega`
`(dL)/(dt)=Gamma`
In noninertial frames

Options

A. both A and B are true
B. A is true but B is false
C. B is true but A is false
D. both and B are false

Answer

To analyze the given equations in the context of non-inertial frames, let's break down the problem step by step.

### Step 1: Understanding the First Equation
The first equation given is:
\[ L = I \omega \]
Where:
- \( L \) is the angular momentum,
- \( I \) is the moment of inertia,
- \( \omega \) is the angular velocity.

In non-inertial frames, the definition of angular momentum remains valid. The moment of inertia \( I \) and angular velocity \( \omega \) are still defined in the same way. Therefore, this equation holds true in non-inertial frames.

### Step 2: Understanding the Second Equation
The second equation is:
\[ \frac{dL}{dt} = \Gamma \]
Where:
- \( \frac{dL}{dt} \) is the rate of change of angular momentum,
- \( \Gamma \) is the torque.

In non-inertial frames, if there are no external torques acting on the body, the total torque would be zero, leading to:
\[ \frac{dL}{dt} = 0 \]
This means that the angular momentum \( L \) remains constant if no external torques are present. However, if we consider the presence of fictitious forces in non-inertial frames, the torque can be affected, and thus the equation may not hold as it does in inertial frames.

### Conclusion
1. The first equation \( L = I \omega \) is **true** in non-inertial frames.
2. The second equation \( \frac{dL}{dt} = \Gamma \) is **false** in non-inertial frames because it does not account for the effects of fictitious forces and torques that can arise in such frames.

### Final Answer
Based on the analysis:
- The first statement is true.
- The second statement is false.

Thus, the correct option is: **A is true but B is false.**

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