Calculate the torque on the square plate of the previous problem if it rorates about a diagonal with the same angular acceleration.

Answer

A

Explanation

Moment of inertial of a square plate about its diagoN/Al is `(ma^2)/12`
(m=mass o the square plate)
a=edges of the square

Therefore torque produced
`((ma^2)/12)xxl`
`({((120xx10^-3xx5.2xx10^-4))/(12 0.2)}`
`=10x25xx10^-7xx0.2`
`=0.5xx10^-5N-m`