Because off the friction between the water is oceans with the earth's surface the rotational kinetic energy of the earth is continuously decreasing. If earth's angular speed decreases by 0.0016 rad/day in 100 years, find the average torque of the friction on the earth. Radius of the earth is 6400 km and its mass is `6.0xx10^24kg`.

Answer

A, B

Explanation

The earth's angular speed decreases by 0.0016 rad/day in 100 years.
Therefore the torque produced by the ocean water in decreasing earth's angular velocity
`tau=Ialpha=2/5mr^2xx(omega-omega_0)/t`
`=2/5xx6xx10^24xx64^2xx10^10`
`xx{0.0016/(86400^2xx10xx365)}`
[1year=365days=365xx86400sec]`
=5.678xx10^20N-m`