A flywheel rotating at a speed of `600` rpm about its axis is brought to rest by applying a constant torque for `10` seconds. Find the angular deceleration and angular velocity `5` second after the application of the torque.

Answer

A, B

Explanation

A wheel rotating at a speed of 600 rpm
`omega_0=600 rpm`
=10 revolutions per second
r=10sec
(in 10 sec it comes to rest)
omega=0`
therefore `omega_0=-at`
`rarr a=-10/10=-`rev/s^2`
rarr omega=omega_0+at`
`=10-1xx5=5rev/s`
Therefore angular deceleration
`=1rev/s^2 and
Angular velocity after 5 sec is 5 rev/s.