Calculate the ratio of the angular momentum of the earth about its axis due to its spinning motion to that about the sun due to its orbital motion. Radius of the earth =6400 km and radius of the orbit of the earth about the sun `=1.5xx10^8km.`

Answer

A, B

Explanation

Angular momentum of the earth about its axis `=2/5mr^2xx((2pi)/86400))`
`(because I=2/5mr^2)`
angular moment of the earth about suns axis
`=mR^2xx((2pi)/86400xx365)`
`(because I=mR^2)`
therefore, ratio of the angular momentum
`=(2/5mr^2xx(2pi/86400)/(mr^2xx2pi/(86400x365)`
`=((2r^2xx365))/(5R^2)=((2.990xx10^10)/(1.125xx10^17))`
`=2.65xx10^-7`