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A wheel of moment of inertia 0.500 kg-m^...

A wheel of moment of inertia `0.500 kg-m^2` and radius 20.0 cm is rotating about its axis at an angular speed of 20.0 rad/s. It picks up a stationary particle of mass 200 g at its edge. Find the new angular speed of the wheel.

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The correct Answer is:
A, D

A whel has `I=0.500 kg-m^2,r=0.2m`
`omega=20rad/s`
statioN/Ary particle =0.2 kg
Therefore `I_1omega_1=I_1omega_2`
[since exterN/Al torque =0]
`rarr 0.5x20=90.5+0.2xx0.22)omega_2`
`rarr omega_2=10/0.508`
`=19.69=19.7rad/s`
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