Suppose the platform with the kid in the previous problemis rotting in anticlockwise directioin at an angular speed `omega`. The kid starts walking along the rim with a speed v relative to the platform also in the anticlockwise direction. Find the new angular speed of the platform.

Answer

A, B

Explanation

From initial frame of reference when we see the (man wheel) systm we can find that the wheel moving a speed of and the man with `(w+v/R)` after the man has started walking.
`omega^1=angualr velocity after walking)`
`omega=angular velocity of the wheel before walking)
Since `^^Ei=0`
Extended torque =0
therefore
`(I+mR^2)omega=Iomega^1=Iomega^1+mR^2(omega^1+v/R)`
`rarr (I+mR^2)omega=Iomega^1+mR^2(omega^1+v/R)`
`rarr (I+mR^2)omega-MvR`
`=(1+mR^2)omega^1`
`rarr omega^I1=((I+MR^2)omega-MvR)/(I+MR^2)`