Consider the situation as shown in the figure. A solid sphere of mass `m` is released from rest from the rim of a hemispherical cup so that it rolls along the surface. Find the normal contact force between the solid sphere and the cup at the bottom most point.

Answer

A

Explanation

Total normal force `=mg+(mv^2)/(R-r)`
`Agin, mg(R-r)=1/2Iomega^2+1/2 mv^2`

`mg(R-r)=1/2x2/5mv^2+1/2mv^2`
rarr 7/10mv^2=mg(R-r)`
`rarr v^2=10/7g(R-r)` Therefore, total normal force
`=mg(m(10/7)g(R-r))/(R-r)`
`=mg+mg(10/7)`
`-(17/7)mg`