A thin spherical shell lying on a rough horizontal surface is hit by as cue in such a way that the line of action passes through the centre of the shell. As a result the shell starts moving with a linear speed v without any initial angualr velocity. Find the linear speed of the shell after it starts pure rolling on the surface.

Answer

C

Explanation

The shell will move a velocity nearly equal to v due to this motion a frictioN/Al force wil act.
In the background direction, for which after some time the shell attains a pure roling.
If we consider moment about A, then it wil be zero.
Therefore Net angular momentum about A before pure rolling.
=net angular moment after pure rolling
`=(2/3)MR^2xx(V_0/R)+(MxV_0xxR)=MVR`
`rarr (5/3)V_0=V`
`rarr V_0=(3V)/5`