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There are three points A, B and C horizontal plane, such that `AB=AC=100`m a varticaly tower is placed on the midpoint of BC, such that angle of elevation of the top of the tower from A is `cot^(-1)(3sqrt(2))` and that from B is `cosec^(-1)(2sqrt(2))` then the height of the tower is

A

`25`

B

`10`

C

`(100)/(sqrt(3))`

D

`20`

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The correct Answer is:
D
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