Pressure of 1 mole ideal is given by P=P_(0)[1-(1)/(2)(V_(0)/(V))^(2)] ,brgt If volume of gas change from V_(0) to 2 V_(0) . Find change in temperature.
One mole of an ideal gas undergoes a process P = P_(0) [1 + ((2 V_(0))/(V))^(2)]^(-1) , where P_(0) V_(0) are constants. Change in temperature of the gas when volume is changed from V = V_(0) to V = 2 V_(0) is:
One mole of an ideal gas undergoes a process p=(p_(0))/(1+((V_(0))/(V))^(2)) . Here, p_(0) and V_(0) are constants. Change in temperature of the gas when volume is changed from V=V_(0) to V=2V_(0) is
One mole of an ideal gas undergoes a process p=(p_(0))/(1+((V)/(V_(0)))^(2)) where p_(0) and V_(0) are constants. Find temperature of the gaas when V=V_(0) .
For one mole of ideal gas if P=(P_(0))/(1+((V)/(V_(0)))) where P_(0) and V_(0) are constant, then temperature of gas when V=V_(0) is:
One mole of an ideal gas passes through a process where pressure and volume obey the relation P=P_0 [1-1/2 (V_0/V)^2] Here P_0 and V_0 are constants. Calculate the change in the temperature of the gas if its volume changes from V_0 to 2V_0 .
One mole of a diatomic gas undergoes a process P = P_(0)//[1 + (V//V_(0)^(3))] where P_(0) and V_(0) are constant. The translational kinetic energy of the gas when V = V_(0) is given by
