If maximum energy is stored in capacitor at t = 0 then find the time after which current in the circuit will be maximum.
In adjacent circuit, switch S is closed at t = 0. The time at which current in the circuit becomes half of the steady current is
Find the value of current I in the circuit
If at t = 0 the switch S_(w) is closed , then the charge on capacitor (initially unchanged)in the given circuit when the current through battery becomes 50 % of its maximum value is (assume battery is ideal)
In the circuit shown in figure-3.344 if battery is ideal , then time after which current in R_(3) becomes (1/e) time that of maximum current through it is :
Find the value of current in circuit
A 20 mH coil is connected in series with a 2 k Omega resistor and a 12 V battery. Calcualte (i) time constant of the circuit, (ii) time during which current decrys to 10% of its maximum value.
