In the circuit diagram of zener diode as shown in figure, when the value of `V_(0)` is `8` volt, the current through zener diode is `i_(1)` and when `V_(0)` is `16` volt, the corresponding current is `i_(2)`. Find the value of `(i_(2)-i_(1))`. (Zener breakdown voltage `V_(2)=6V)`
Find the current through Zener diode.( Ans in "mA" and breakdown voltage is V(z)=10V )
In the given circuit,the breakdown voltage of the Zener diode is "3.0V" .What is the value of I_(z) ?
For the circuit shown in figure, Find (1) the output voltage , (2) the voltage drop across series resistance , (3) the current through Zener diode. .
In the figure, the reverse breakdown voltage of a Zener diode is 5.6V, then the current I_(Z) through the diode is
for the circuit shown in figure, find (i). The output voltage (ii). The votlage drop across series resistance (iii). The current through zener diode.
From the zener diode circuit shown in the figure, find (1) the output voltage (2) the voltage drop across series resistance and (3) the current through zener diode.
A Zener diode of breakdown voltage "10V" is used as a voltage regulator as shown in the figure. The current through the Zener diode is:
A zener diode of 30 V is connected as shown with 90 V battery as shown in figure. Calculate the current passing through the diode.
If voltage across zener diode is 6V then find out value of maximum resistance in this condition.
In the circuit shown below, assume the diode to be ideal. When V_(i) increases from 2 V to 6 V, the change in the current in (in mA)
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