A steel wire of length 2.0 m/s is stretched through 2.0 mm. The cross sectional area of the wire is 4.0 mm^2. Calculate the elastic potential energy stored in the wire in the stretched condition. Young modulus of steel `=2.0x10^11Nm^-2`

Explanation

To calculate the elastic potential energy stored in a steel wire that is stretched, we can follow these steps:

### Step 1: Identify the given values
- Length of the wire, \( L = 2.0 \, \text{m} \)
- Change in length (stretch), \( \Delta L = 2.0 \, \text{mm} = 2.0 \times 10^{-3} \, \text{m} \)
- Cross-sectional area, \( A = 4.0 \, \text{mm}^2 = 4.0 \times 10^{-6} \, \text{m}^2 \)
- Young's modulus of steel, \( Y = 2.0 \times 10^{11} \, \text{N/m}^2 \)

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