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In a ring of mass 0.5 kg and radius sqrt...

In a ring of mass 0.5 kg and radius `sqrt(5)`m, to produce angular acceleration of `18rad//s^(2)` in this body, applied torque (in N-m) should be

A

7.2

B

0.14

C

45

D

450

Text Solution

Verified by Experts

The correct Answer is:
C
Moment of inerrtia of the ring, `l=MR^(2)=0.5xx5=2.5kgm^(2)`
Applied torque is
`tau=lalpha=2.5xx18=45N-m`
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