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What percent of length of a wire will i...

What percent of length of a wire will increses by applying a stress fo `1kg. Wt//mm^(2)` on it.
`[Y = 1xx10^(11) Nm^(-2) "and" 1 kg wt = 9.8N]`

A

`0.0078%`

B

`0.0088%`

C

`0.0098%`

D

`0.0067%`

Text Solution

Verified by Experts

The correct Answer is:
C
Strain`=(Deltal)/(l)=("Stress")/(Y)=(9.8xx10^(6))/(1xx10^(11))`
`=9.8xx10^(-5)`
`therefore%` increase in length
`=(Deltal)/(l)xx100`
`=9.8xx10^(-5)xx100`
`=0.0098%`
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