Home
Class 12
PHYSICS
If the binding energy per nucleon in .(3...

If the binding energy per nucleon in `._(3)Li^(7)` and `._(2)He^(4)` nuclei are respectively `5.60` MeV and `7.06` MeV, then the ebergy of proton in the reaction `._(3)Li^(7) +p rarr 2 ._(2)He^(4)` is

A

19.6 MeV

B

`-2.4MeV`

C

`8.4MeV`

D

`17.3MeV`

Text Solution

Verified by Experts

The correct Answer is:
D
According to the question, binding enerrgy `._(3)^(7)Li` nucleus
`=7xx5.60MeV=39.2MeV`
Binding energy of `._(2)^(4)He` nucleus
`=4xx7.06MeV=28.24MeV`
the reaction is
`._(3)^(7)Li+._(1)^(2)H to 2(._(2)^(4)He)+Q`
`thereforeQ=2(BE" of "._(2)^(4)He)-(BE" of "._(3)^(7)Li)`
`=2xx2824MeV-39.2MeV`
`=56.48MeV-39.2MeV`
`=17.28MeV=17.3MeV`
Promotional Banner

Topper's Solved these Questions

  • PRACTICE SET 03

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise PAPER 2 (MATHEMATICS)|1 Videos

  • PRACTICE SET 02

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise Paper 1 (Physics)|50 Videos

  • PRACTICE SET 04

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise PAPER 1 (PHYSICS & CHEMISTRY)|50 Videos

Similar Questions

Explore conceptually related problems

If the binding energy per nucleon in ._(3)Li^(7) and ._(2)He^(4) nuclei are respectively 5.60 MeV and 7.06 MeV, then the energy of proton in the reaction ._(3)Li^(7) +p rarr 2 ._(2)He^(4) is

If the binding energy per nucleon in L i^7 and He^4 nuclei are respectively 5.60 MeV and 7.06 MeV . Then energy of reaction L i^7 + p rarr 2_2 He^4 is.

If the binding energy per nucleon in ._(3)^(7)Li and ._(2)^(4)He nuclei are 5.60 MeV and 7.06 MeV respectively, then in the reaction p+._(3)^(7)Lirarr2._(2)^(4)He energy of proton must be:

If the binding energy per nucleon in _(3)^(7) Li and _(2)^(4)He nuclei are 5.60 MeV and 7.06MeV respectively then in the reaction P +_(3)^(7) Li rarr 2 _(2)^(4) He energy of proton mnust be

The binding energy per nucleon of ._(3)^(7) Li and ._(2)^(4)He nuclei are 5.60 MeV and 7.06 MeV, respectively. In the nuclear reaction ._(3)^(7)Li+._(1)^(1)H rarr ._(2)^(4)He+._(2)^(4)He+Q , the value of energy Q released is

The binding energy per nucleon for ._(3)Li^(7) will be, if the mass of ._(3)Li^(7) is 7.0163 a.m.u.

The binding energy per nucleon for ""_(1)H^(2) and ""_(2)He^(4) are 1.1 MeV and 7.1 MeV respectively. The energy released when two ""_(1)H^(2) to form ""_(2)He^(4) is ………….. MeV.

Binding energy per nucleus of ._(1)^(2)H and ._(2)^(4)He are 1.1 MeV and 7 MeV respectively. Calculate the amount of energy released in the following process: ._(1)^(2)H + ._(1)^(2)H to ._(2)^(4)He

Calculate the energy of the reaction , Li^(7) + p to 2 _(2)He^(4) If the binding energy per nucleon in Li^(7) and He^(4) nuclei are 5.60 MeV and 7.06 MeV , respectively .