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The acceleration due to gravity at a pla...

The acceleration due to gravity at a place is `pi^(2)m//s^(2)`. Then, the time period of a simple pendulum of length 1 m is

A

`(2)/(pi)s`

B

`2pis`

C

`2s`

D

`pis`

Text Solution

Verified by Experts

The correct Answer is:
C
Time period of simple pendulum is
`T=2pisqrt((l)/(g))=2pisqrt((1)/(pi^(2)))=2s`
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