The Temperature at which 28 g of N(2) wi...

The Temperature at which 28 g of `N_(2)` will occupy a volume of 10.0 L at 2.46 atm is

A

299.6 K

B

`0^(@)C`

C

`273K`

D

`10^(@)C`

Text Solution

Verified by Experts

The correct Answer is:

A

28g `N_(2)=1" Mol of "N_(2)`
Applying, pV=nRT
`2.46xx10=1xx.0821xxT`
`thereforeT=299.6K`

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