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The equation 12x^(2)+7xy+ay^(2)+13x-y+3=...

The equation `12x^(2)+7xy+ay^(2)+13x-y+3=0` represents a pair of perpendicular lines. Then, the value of a is

A

`(7)/(2)`

B

`-19`

C

`-12`

D

`12`

Text Solution

Verified by Experts

The correct Answer is:
C
On comparing the given equation with standard equation, we get a=12 and b=a, for perpendicular lines
Coefficient of `x^(2)+`coefficient of `y^(2)=0`
`therefore12+a=0impliesa=-12`
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