A force vecF=(5hati+3hatj)N is applied o...

A force `vecF=(5hati+3hatj)N` is applied over a particle which displaces it from its original position to the point `vecs=S(2hati-1hatj)m`. The work done on the particle is

`-7`

`+7`

`+10`

`+13`

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Verified by Experts

The correct Answer is:

Work done is displacing the particle
`W=F*r`
`=(5hati+3hatj+2hatk)*(2hati-hatj)`
`=5xx2+3xx(-1)+2xx0=10-3`
`=7Nm=7J`

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