A body of mass 10 kg is acted upon by two forces each of magnitude 10 N making an angle of `60^(@)` with each other. Find the net acceleration of the body

Options

A. `2sqrt(3)ms^(-2)`
B. `sqrt(3)ms^(-2)`
C. `3sqrt(3)ms^(-2)`
D. `4sqrt(3)ms^(-2)`

Answer

B

Explanation

Resultant force
F net`=sqrt(F_(1)^(2)+F_(2)^(2)+2F_(1)F_(2)costheta)`
`=sqrt((10)^(2)+(10)^(2)+2xx10xx10cos60^(@))`
`=sqrt(100+100+00)=10sqrt(3)`
Mass of the body=10 kg
Acceleration`=("force")/("mass")=(10sqrt(3))/(10)`
`=sqrt(3)m//s^(2)`